Question

If 1/x, 1/y, 1/z are in AP, then Y is equal to

Answer 1

1/x,1/y,1/z are in AP then

2/y=1/x+1/z

2/y=x+z/zx

y=2zx/z+x

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Answer 2

The value of y is  $y=\frac{2zx}{x+z}$.

Step-by-step explanation:

Given : If 1/x, 1/y, 1/z are in AP.

To find : The value of y ?

Solution :

We know that, In A.P the difference between two consecutive terms are same.

i.e. Second term - first term = third term - second term

Here, First term = $\frac{1}{x}$

Second term = $\frac{1}{y}$

Third term = $\frac{1}{z}$

Substitute the value,

$\frac{1}{y}-\frac{1}{x}=\frac{1}{z}-\frac{1}{y}$

$\frac{1}{y}+\frac{1}{y}=\frac{1}{z}+\frac{1}{x}$

$\frac{2}{y}=\frac{x+z}{zx}$

$y=\frac{2zx}{x+z}$

Therefore, the value of y is  $y=\frac{2zx}{x+z}$.

#Learn more

If 1/x, 1/y , 1/z are in AP show that (y+z)/x, (x+z)/y, (x+y)/z

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