If 1/x+2 ,1/x+3 and 1/x+5 are in A.P find x
Answers
Answered by
5
Answer:
in A.p
a2 -a1 = a3 - a2
Step-by-step explanation:
then,
here
a1= 1/x+2
a2 =1/x+3
a3=1/x+5
1/x+3 -( 1/x+2) = 1/x+5 -(1/x+3)
Answered by
8
Answer:
a1=1/x+2
a2=1/x+3
a3=1/x+5
common difference=a2 - a1=a3 - a2
2(a2)=a3+a1
2(1/x+3)=1/x+2 + 1/x+5
2/x+3=(x+5+x+2)/(x+2)(x+5)
2/x+3=(2x+7)/x^2+7x+10
2x^2+14x+20=2x^2+13x+21
14x - 13x=20 - 21
x=1
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