If (1 + x)²ⁿ = a₀ + a₁ x + a₂ x² + ... + a₂n x²ⁿ, then
(a₀ - a₂ + a₄ - a₆ + ... - a₂n)² + (a₁ - a₃ + a₅ - a₇ + ... + a₂n₋₁)² is
equal to
(a) 2ⁿ (b) 4ⁿ (c) 0 (d) none of these
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Answer:
option c
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