Question

if (1/x+x)^2=100 then 1/x^2+x^2=

Answer 1

Hi friend
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Your answer
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$( \frac{1}{x} + x) {}^{2} = 100 \\ \\ = > ( \frac{1}{x} ) {}^{2} + 2 \times ( \frac{1}{x} ) \times (x) + (x) {}^{2} = 100\\ \\ = > \frac{1}{x {}^{2} } + 2 + x {}^{2} = 100 \\ \\ = > \frac{1}{x {}^{2} } + x {}^{2} = 100 - 2 \\ \\ = > \frac{1}{x {}^{2} } + x {}^{2} = 98$
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