if 1-x8 = 65 and 1-x4=64 then what is x
1/2 x root2, root2, 1/root2, 2root2, 3root2
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Answer: Let 1- x8 = 65 ------------------(1)
And,
1 - x4 = 64 -------------------(2)
Now simplify equation 1 , As:
18 - x8 = 65
⇒(14)2 − (x4)2 = 65
⇒(14 − x4)(14 + x4) =65 [We know (a2 − b2) = (a - b ) (a + b) ]
From equation (2) 1 - x4 = 64 , substitute that value and get
⇒ 64 (14 + x4) = 65
⇒ (14 + x4) = 6564
⇒x4 = 6564 - 1
⇒x4 = 164
⇒x4 = 12×2×2×2×2×2
⇒x4 = 124 22
Multiply in power on both side by 14, we get
⇒x = 122√ (Ans)
And,
1 - x4 = 64 -------------------(2)
Now simplify equation 1 , As:
18 - x8 = 65
⇒(14)2 − (x4)2 = 65
⇒(14 − x4)(14 + x4) =65 [We know (a2 − b2) = (a - b ) (a + b) ]
From equation (2) 1 - x4 = 64 , substitute that value and get
⇒ 64 (14 + x4) = 65
⇒ (14 + x4) = 6564
⇒x4 = 6564 - 1
⇒x4 = 164
⇒x4 = 12×2×2×2×2×2
⇒x4 = 124 22
Multiply in power on both side by 14, we get
⇒x = 122√ (Ans)
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