If 1 zero of a polynomial x^2+a is -3, then find its other zero. pls help
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Answered by
5
hey
p(x) = x^2 + a
p(-3) = (-3)^2 + a = 0
9 + a = 0
a = -9
x^2 - 9 = 0
x^2 = 9
x = +3 and x = -3
therefore the other zero is 3
Anonymous:
Thank you
but other answer is -6 how is it possible
My pleasure
is it sure the answer is 3
he is wrong because 3square is 9 but not 6
yes bro its 3
thanks
my pleasure (×_×)
Answered by
0
if one zero is -3
then, x^2 + a = (-3)^2+a = 0
= 9+a=0
therefore, a=-9
so, other roots of the polynomial are
= x^2 + a = x^2 + 9 = 0
so x = -3 or x = 3
then, x^2 + a = (-3)^2+a = 0
= 9+a=0
therefore, a=-9
so, other roots of the polynomial are
= x^2 + a = x^2 + 9 = 0
so x = -3 or x = 3
but how
now see
i have just edited
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