Question

if (10^11+25)^2 -(10^11-25)^2=10^n then find the value of n​

Answer 1

The final answer is 13.

Step-by-step explanation:

$\ Given \ value:\\\\ (10^{11}+25)^2 -(10^{11}-25)^2=10^n\\\\\ Find:\\\\n= ?\\\\\ Solution:\\\\\ formula: \\\\ a^2-b^2 = (a+b)(a-b) \\\\\ (10^{11}+25)^2 -(10^{11}-25)^2=10^n\\\\\ (10^{11}+25+10^{11}-25) ((10^{11}+25)-(10^{11}-25)) = 10^n \\\\\ (10^{11}+10^{11}) (10^{11}+25-10^{11}+25) = 10^n \\\\\ (10^{11}+10^{11}) (25+25) = 10^n \\\\\ (2 \times 10^{11}) (50) = 10^n \\\\\ 100 \times 10^{11} = 10^n \\\\\ 10^2 \times 10^{11} = 10^n \\\\\ 10^{13} = 10^n \\\\n= 13$

Learn more:

• Find the value: https://brainly.in/question/12658636

Answer 2

Answer:

The answer is 13 / the value of n is 13