Question

If 10 – 19, 20-29, 30-39 are the three class intervals of the frequency distribution then the upper boundary of the class interval 20 -29. Is _____________.

Answer 1

Answer:

i think it will be 29 because it is in discontinuous

Answer 2

Given:

Class interval $= 20-29$

To find:

To find the upper boundary of the class interval.

Step-by-step explanation:

• The upper boundary is the average of the upper and the lower limit of the class.
• It can be easily obtained y using the formula

Solution:

upper boundary $= \frac{upper limit + lower limit}{2}$

now,

$= 20-19\\\\=1$

Now average it out

$= \frac{1}{2}\\\\= 0.5$

Now we will subtract this from the upper limit and add it to the lower limit

$20 - 0.5 = 19.5\\\\29 + 0.5 = 29.5$

Hence, the upper boundary of the class interval is $19.5$