If 10 – 19, 20-29, 30-39 are the three class intervals of the frequency distribution then the upper boundary of the class interval 20 -29. Is _____________.
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Answer:
i think it will be 29 because it is in discontinuous
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Given:
Class interval
To find:
To find the upper boundary of the class interval.
Step-by-step explanation:
- The upper boundary is the average of the upper and the lower limit of the class.
- It can be easily obtained y using the formula
Solution:
upper boundary
now,
Now average it out
Now we will subtract this from the upper limit and add it to the lower limit
Hence, the upper boundary of the class interval is
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