Math, asked by viratmankali, 8 months ago

If 10 – 19, 20-29, 30-39 are the three class intervals of the frequency distribution then the upper boundary of the class interval 20 -29. Is _____________.

Answers

Answered by chatterjeechandra201
5

Answer:

i think it will be 29 because it is in discontinuous

Answered by hotelcalifornia
1

Given:

Class interval = 20-29

To find:

To find the upper boundary of the class interval.

Step-by-step explanation:

  • The upper boundary is the average of the upper and the lower limit of the class.
  • It can be easily obtained y using the formula

Solution:

upper boundary = \frac{upper limit + lower limit}{2}

now,

= 20-19\\\\=1\\\\

Now average it out

= \frac{1}{2}\\\\= 0.5

Now we will subtract this from the upper limit and add it to the lower limit

20 - 0.5 = 19.5\\\\29 + 0.5 = 29.5

Hence, the upper boundary of the class interval is 19.5

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