Math, asked by UNIQUEamit, 1 year ago

if 10^2y=25 ,then 10^-y equals

Answers

Answered by parisakura98pari
0
Given ,    10 ^2y = 25

=  2y = Log 25
= y =  (Log 25) /2 = Log 5

Now,  10 ^ -y = 10 ^ - Log 5  =  10 ^ Log (1/5)  = 1/5 ^ Log 10 = 1/5

PROPERTIES USED ARE : REFER TO THE FILE ATTACHED BELOW.

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