Math, asked by deepak14397, 1 year ago

if 10^2y =25, then find 10^-y​

Answers

Answered by sghosh31
2

(10^y)^2=5^2

10^y=5

(10^y)^-1=(5^)-1

10^-1=1/5(Ans)

Answered by swaroopsinha3
1

Answer:

Step-by-step explanation:(10^-Y)^-2=5²

(1/10^-y)^-2=5²[cancel squares]

1/10^-y=5

10^-5=1/5

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