if 10^2y =25, then find 10^-y
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Answered by
2
(10^y)^2=5^2
10^y=5
(10^y)^-1=(5^)-1
10^-1=1/5(Ans)
Answered by
1
Answer:
Step-by-step explanation:(10^-Y)^-2=5²
(1/10^-y)^-2=5²[cancel squares]
1/10^-y=5
10^-5=1/5
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