Question

If 10^2y=25, then find the value of 10^ (-y).

Answer 1

hi friend,

10^2y=25

10^2y=5²

10^y=5

10^-y=5^-1=1/5



I hope this will help u ;)

Answer 2

Answer:

$The \: value \: of\: 10^{-y}=\frac{1}{5}$

Step-by-step explanation:

$Given \: (10)^{2y}=25$

$\implies (10^{y})^{2}=5^{2}$

$By\: Exponential \: law :</p><p>\boxed {a^{mn}=(a^{m})^{n}}$

$\implies 10^{y} = 5--(1)$

$Now,\\The \: value \: of\: 10^{-y}\\=\frac{1}{10^{y}}$

\* By Exponential Law:

$\boxed {a^{-n}=\frac{1}{a^{n}}}$*\

$=\frac{1}{5}$ \* From (1)

Therefore,

$The \: value \: of\: 10^{-y}=\frac{1}{5}$

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