Question

If (10)⁹ + 2(11)¹(10⁸)+ 3(11)²(10)⁷ + ..... +10(11)⁹ = k (10)⁹, then k is equal to:
(a) 100
(b) 110
(c) $\frac{121}{10}$
(d) $\frac{441}{100}$

Answer 1

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