If 10^9 electrons move out of a body to a another body every second then how much time is required to get a charge of 1c
Answers
Answered by
176
we know that 1 Coulomb = 6.242×1018 eletrons
given 10^9 electrons take 1 secs
=> 10^9 electrons ------> 1 sec
=> 1 electrons ---------> 1/(10^9) secs
=> 6.242×1018 ------> 6.242×1018/ (10^9)
= 6.242×109 secs = 6.242×109/ (60*60*24*365) years
=197.93 years
given 10^9 electrons take 1 secs
=> 10^9 electrons ------> 1 sec
=> 1 electrons ---------> 1/(10^9) secs
=> 6.242×1018 ------> 6.242×1018/ (10^9)
= 6.242×109 secs = 6.242×109/ (60*60*24*365) years
=197.93 years
Answered by
151
Answer
In one second 10^9 electrons move out of the body.
Explanation
Charge of one electron= 1.6×10^-19 C
Charge of 10^9 electrons = 1.6×10^-19 C × 10^9
= 1.6×10^-10 C
We can say,1.6×10^−10 C of charge move out of the body to another body every second.
The time required to get a total charge of
1C = 1sec/1.6×10^-10 C
= 6.25×10^9 / 365×24×3600
= 197.8 years or approximately 198 years.
Hope it helps ! !
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