Physics, asked by JUSHU1128, 1 year ago

If 10^9 electrons move out of a body to another body every second. How much time is required to get a total charge of 1C on the other body?

Answers

Answered by YashParitkar
2
Hence the answer is 6.25 × 10^8.
Hope you understand calculations.
Attachments:
Answered by abu7878
9

Answer:

197.93 years are required to get a total charge of 1C on the other body.

Explanation:

The charge on electron with 10^{9} \mathrm moves out of the body every second to another body. Time taken to get a 1 C of charge on the other body be calculated as following –

As we know that, the 1 C =  \bold{6.242 \times 10^{18}} electrons

Thereby, applying unitary method, we have –

10^{9} \mathrm 9 electrons moves out every second

1 electron moves out in  1 / 10^{9} seconds

1 C will be moved out in \left(\frac{1}{10^{9}} \times 1 C\right) seconds

6.242 \times 10^{18} electron moved out in \frac{1}{10^{9}} \times 6.242 \times 10^{18}

Therefore time taken will be 6.242 \times 10^{9} seconds

Time = 6.242 \times 10^{9} seconds = \left(6.242 \times 10^{9}\right) / 60 \times 60 \times 24 \times 365

Time = 197.93 years.

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