Question

If 10 A of current passes through cross-section of a wire for 30 second,Find the amount of Charge passed through it? 10a o

Answer 1

Given :-

Current of the cross-section of the wire = 10 A

Time taken by the wire = 30 sec

To Find :-

The amount of charge passed through the wire.

Analysis :-

Here we are given with the current and time taken by the wire.

In order to find the charge substitute the given values in the question such that current is equal to charge divided by time and find the charge passed through the wire accordingly.

Solution :-

We know that,

• i = Current
• q = Charge
• t = Time

Using the formula,

$\underline{\boxed{\sf Current=\dfrac{Charge}{Time} }}$

Given that,

Current (i) = 10 A

Time (t) = 30 sec

Substituting their values,

⇒ i = q/t

⇒ 10 = q/30

⇒ q = i × t

⇒ q = 10 × 30

⇒ q = 300 C

Therefore, the charge passed through the wire is 300 C.

Answer 2

Answer:

Given :-

• A 10 A of current passes through cross section of a wire for 30 seconds.

To Find :-

• What is the amount of charge passed through it.

Formula Used :-

We know that,

➤ I = Q/t

Hence, we have to find the charge,

★ Q = It ★

where,

• Q = Charge
• I = Current
• t = Time

Solution :-

Given :

• Current = 10 A
• Time = 30 seconds

According to the question by using the formula we get,

↦ Q = 10 × 30

➠ Q = 300 C

∴ The charge passed through it is 300 C .

✪ Extra Information ✪

✧ Current :-

• Current is a flow of electrical charge carriers, usually electrons atoms.
• The S.I unit of current is ampere (A).
• Formula for current is I = V/R, where I = Current, V = Voltage, R = Resistance.

✧ Charge :-

• Charge is the property of subatomic particles that causes it to experience a force when placed in an electromagnetic field.
• S.I unit of charge is coloumb (C).
• Formula for charge is Q = It, where Q = Charge, I = Current, t = Time.

✧ Time :-

• Time can be defined as the dimension based on which the evolution of any system takes place.
• The S.I unit of time is second (s).
• Formula for time is t = d/s, where t = Time, d = Distance, s = Speed.