Question

if 10 bulbs are lighted 4 hours every day for 60 days then the electricity bill is Rs.80. How many bulbs can be lighted for 3 hours every day for 16 days so that the electricity bill is rs. 40?









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Answer 1

Answer:

Two electric bulbs of 100 W each is used for 10 hours in the month of June. Write the following steps in sequential order to find the numbe of units of electricity consumed in the month of June. <br> (A) The number of units of electricity consumed by both bulbs in the month of June is the total elec-trical energy consumed by bulbs expressed in W h divided by 100 W h . <br> (B) Note the rated power of each electric bulb, time of electrical consumption of each bulb per day from the given data. <br> (C ) We know, one electrical unitor.<br> (D) Calculate the amount of electrical energy con-sumed by both the bulbs in the month of June using, (sum of the electrical power of both the bulb)(time of consumption in one day)days.



Text Solution

BACD

ABCD

BDCA

DCBA

Answer :

C

Solution :

The power of electric bulb,

. <br> The time for which bulb utilieses electric power per day

h. <br> In the month of june,

days

. <br> The electric energy consumed by a bulb is

<br>

<br>

<br> The total energy consumed by both the bulbs, <br>

. <br>

The number of electric units

units. <br>

Answer 2

Energy = Power*time

Energy consumed by 100 W bulb per day = 2∗100 Wh = kWh

Energy consumed by 40 W bulbs per day = 4∗40∗4 Wh0.6kWh

Total energy consumed per day = 0.2 + 0.64 kWh

= 0.84 kWh

Therefore, the energy consumed in 30 days = 30∗0.84 = 25.2

kWh