If 10 capacitors of 1uf (1 micro farad) are connected in parallel with a 2 volt battery then what is the voltage across each one of them?? Please anyone help.
Answers
5 coloumb will be the charge value.
Given: 10 capacitors of 1uf (1 micro farad) are connected in parallel with a 2 volt battery
To find: Charge
Solution:
Inductance:
• Self-inductance is the possessions of the current-winning coil that oppose or opposes the change of current abounding through it.
• This happens for the most part on account of the self-persuaded emf created in the coil itself. In natural agreements, we can still mention that self-inductance is a wonder place skilled is the initiation of a service in a current-moving strand.
• The self-persuaded emf present in the coil will withstand the rise of current when the current increases and it will likewise oppose the fall of current if the current decreases. In essence, the course of the persuaded emf is opposite to the used strength if the current is growing and the route of the persuaded emf is aligned as the used generated power if the current is dropping.
• The above characteristic of the coil survives only for the changeful current that is the altering current and other than the direct or stable current. Self-inductance is continually antagonistic the changeful current and is calculated in Henry (SI whole).
Q=CV
Lets simplify it,
Q= charge through capacitor
C=capacitances
V=voltage across capacitors
Equivalent capacitorance here will be 0.5 farad
So from above Q=0.5*10=5 coulomb
So charge in both capacitors will remain same which will be 5 coulomb.
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