if 10 coulomb charge flows in 2 second in a 20 ohm resistor then potential difference across its
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1
Answer:
1/20
Explanation:
Q= 2c
time= 2 seconds
r= 20 ohm
potential difference= ?
formula= v=ir
so I = charge÷time
I=2÷2
I= 1
v= ir
=1/20
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