Question

if 10 engines consumes 20kg of coal ,when eacch is working 12 hours a day ,how much coal will be required for 9 engines each running 15 hours a day

Answer 1

9 engine working 15 hour will consume 22.5 kg coal

Answer 2

Answer:

22.5 kg coal is required for 9 engines each running 15 hours a day.

Step-by-step explanation:

Given : 10 engines consumes 20 kg of coal .

           Each engine is working 12 hours a day .

To Find :

How much coal will be required for 9 engines each running 15 hours a day?

Solution :

Since 10 engine consumes 20kg of coal .

So, 1 engine consumes coal = 20/10 = 2 kg

Since 1 engine works 12 hours a day

So, 1 engine consumes coal in 12 hours = 2 kg

So, 1 engine consumes coal in 1 hour = 2/12 kg

Thus 1 engine consumes coal in 15 hour = (2/12)*15 = 2.5 kg

So, 9 engine consumes coal each running 15 hours a day = 2.5*9=22.5 kg

Hence 22.5 kg coal is required for 9 engines each running 15 hours a day.