Question

if 10 g metal oxide contain 9 g of metal then the equivalent weight of the metal will be​

Answer 1

Answer:

144gm

Ratio of metal and oxygen will be 9:1

For 16 g oxygen metal will be 144g

Answer 2

Given,

10 g metal oxide contains 9 g of metal

To Find,

The equivalent weight of the metal will be =?

Solution,

We can solve the question as follows:

It is given that 10 g of metal oxide contains 9 g of metal. We have to find the equivalent weight of the metal.

$Weight\: of\: the\: metal\: oxide = 10\: g$

$Weight\: of\: the\: metal= 9\: g$

The weight of oxygen in the metal oxide will be equal to the weight of the metal subtracted from the weight of the metal oxide. Therefore,

$Weight\: of\: oxygen = 10 - 9 = 1\: g$

Now,

$\frac{Equivalent\: weight\: of\: the\: metal}{Equivalent\: weight\: of\: oxygen} = \frac{Weight\: of\: metal}{Weight\: of\: oxygen}$

The equivalent weight of the oxygen molecule will be 8 g.

Substituting the values in the above formula,

$\frac{Equivalent\: weight\: of\: the\: metal}{8} = \frac{9}{1}$

$Equivalent\: weight\: of\: the\: metal = 9*8 = 72\: g$

Hence, the equivalent weight of the metal is 72 g.