If 10 g of ice at 0°C mixes with 10 g of water at 10°C, then the final temperature t is given by-
(a) (10 x80) + 10 (-0) = 10 (10-t)
(b)10 x80 = 10 (10-t) + 10 (t-0)
(c) t= 5°C
(d) t = 0°C
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Answer: (c)5°C
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