Question

If 10 grams of AgNO3 is available, what volume of 0.25 M AgNO3 solution can be prepared?

Answer 1

moles = 10/170

0.25 = (10/170)/volume

volume = 0.25x170/10 = 4.25

Answer 2

Answer:

240 mL

Explanation:

10 g AgNO$_3$  x  $\frac{1 mol AgNO_3}{169.9g}$  x  $\frac{1L}{0.25 mol AgNO_3}$  = 0.24 L = 240mL