Question

If 10 grams of ice is 80 degrees mixer with 10 g of water at 30 degrees then find the resultant temperature of the mixture​

Answer 1

Answer:

Example

Heat absorbed by ice =mL

f

+ms△Tice

△Q

absorb

=(10)(80)+(10)(1)(T−0)

Heat released by water = M8 △T

water

△Q release = 10(1)(100-T)

Note : △T ice is the temperature change

in water that has been converted from water.

So, △Q absorb = △Q release

⇒800+10T=1000−10T

⇒T=10

∘

C