Question

If 10 grams of the ice at 00C is mixed with 10 grams of water at 1000C, then the final temperature of the mixture will be

Answer 1

Given:

Quantity of ice = 10gm

Quantity of water = 10gm

Latent heat of fusion of ice = 80 cal

Temperature = 1000°C

To Find:

Final temperature of the mixture

Solution:

Mass of water = 10

Mass of ice = 10

Let the final temperature of mixture be = T

Amount of heat lost by water

= 10 × 1 × ( 1000 - T)

Amount of heat gained by ice

= 10 × 80 + 10 × 1 ( T - 0)

Thus,

Heat lost = Heat gained

10 × 1 × ( 1000 - T)  = 10 × 80 + 10 × 1 ( T - 0)

10000 - 10T = 80 + T

11T = 920

T = 83.6

Answer : The final temperature of mixture is 83.6°C