Question

if 10 joule of heat is given to the system and 2 joule work is done by the system then change in internal energy is​

Answer 1

Answer:

Solution:- (C) −10J

As the heat is given to the system and work is done by the system, therefore,

q=+10J

W=−20J

Now from the first law of thermodynamics,

ΔU=q+W

⇒ΔU=10+(−20)=−10J

Hence the change in internal enrgy is =10J.

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Answer 2

Answer:

ans is 8

Explanation:

10j is given and 2j work done by system so ans is 8.