Question

if 10 square theta is equal to 1 minus A square then prove that sec theta + tan cube theta cosec theta is equal to under bracket 2 minus A square under (3 by 2​

Answer 1

Sec theta+tan^3theta×cosec theta=sec theta(1+tan^2theta)

=sec theta(1+1-a^2)=√(1+tan^2 theta)×(2-a^2)=√(1+1-a^2)×(2-a^2)=

\sqrt[2 \div 3]{2 - {a}^{2} }