Question

if 10 theta = 1/ root 7
show that cosec ² theta - sec ²theta
upon cosec²theta + sec²theta =3/4​

Answer 1

Step-by-step explanation:

$tanθ= \frac{1}{ \sqrt{7} } \\ ⟹cotθ=\sqrt{7} \\ we \: know \: \\ sec ^{2} θ=1+tan^{2}2θ \\ ⟹1+ { \frac{1}{ \sqrt{7} } }^{2} \\ ⟹ \frac{8}{7} \\ cosec^{2}θ=1+cot^{2}2θ \\ ⟹1 + \sqrt{7} ^{2} \\ ⟹1+7⟹8 \\ now \\ \frac{ cosec^{2}θ - sec^{2}θ}{cosec^{2}θ + sec^{2}θ }\\ ⟹ \frac{8 - \frac{8}{7} }{8 + \frac{8}{7} } \\ ⟹ \frac{48}{54} \frac{3}{4}$

Answer 2

Answer:

Hope it helps.........