If 10 times of 10th term is equal to 20 times of 20th term of an A.P., find its 30th term.
Answers
Answer:
Step-by-step explanation:
let x be first term and a be the common difference
10th term = x+9a
20th term=x+19a
30th term=x+29a
given
10*10th term=20*20th term
10(x+9a)=20(x+19a)
10x+90a=20x+380a
20x-10x+380a-90a=0
10x+290a=0
10(x+29a)=0
x+29a=0
30th term=0
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✤ Required Answer:
✒ GiveN:
- 10 times 10th term = 20 times 20th term
✒ To FinD:
- Find its 30 th term...?
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✤ How to Solve?
The above question is of AP, Arithmetic progression. Before solving the question, let's know something about arithmetic progression.
- Arithmatic progression is a type of sequence with numbers(terms) where difference between consecutive terms is constant.
- This difference is known as Common difference. This is helpful to prove whether a sequence is a AP.or not.
- General general of AP is a, a + d, a + 2d, a + 3d....Where a = First term, and d = common difference.
☯️ For finding the nth term of AP, Formula:
Where, n is the number of terms.th
So, By using this formula, Let's solve the question...
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✤ Solution:
Let,
- a = first term
- d = common difference
Then, 10th term,
➙ a10 = a + (10 - 1)d
➙ a10 = a + 9d
&
And, 20th term,
➙ a20 = a + (20 - 1)d
➙ a20 = a + 19d
Given, ATQ
➙ 10(a + 9d) = 20(a + 19d)
➙ 10a + 90d = 20a + 380d
➙ 20a - 10a = 90d - 380d
➙ 10a = -290d
➙ 10a + 290d = 0
➙ 10(a + 29d) = 0
➙ a + 29d = 0
To find, 30th term
➙ a30 = a + (30 - 1)d
➙ a30 = a + 29d
And, we got that,
➙ a + 29d = 0
➙ a30 = 0
✒ 30th term of the AP = 0
☀️ Hence, solved !!
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