Question

If 10^x = 64, find the value of :
10^ [(x/2)+1]​

Answer 1

Answer:

Given equation 10^x=64

Taking log on both sides

log(10^x) = log(64)

xlog10 = log (8^2)

x = 2log(8). (log 10=1)

x= 2log(2^3)

x=6log2

x = 6*0.301. (log2=0.301)

x= 1.806

Therefore the value of X=1.086

Step-by-step explanation:

Hope it helpful

Answer 2

Answer:

10000

Step-by-step explanation:

10^ x =2^6

x=6

=(x/2)+1

=(6/2)+1

=3+1

=4

10^4

=10*10*10*10

=10000