if 10 y=7x-4 and 12x+18y=1; find the value of 4x+6y and 8y-x
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Rewriting the given equations, we get
7x−10y=4 ...(i)
12x+18y=1 ...(ii)
On multiplying (i) by 12 and (ii) by 7 and subtracting, we get
84x−120y=48
−
8
4x
−
+
126y=
−
7
−246y=41
∴y=
246
−41
On putting y=
246
−41
in (i), we get
7x−10×
246
−41
=4⇒x=
246
82
Now, 4x+6y=4×
246
82
+6×
246
−41
=
246
82
=
3
1
and
8y−x=8×
246
−41
−
246
82
=
246
−810
=
3
−5
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