Question

If 100 g of a metal oxide contains 32 g of oxygen then the equivalent weight of metal will be
O 17
o 25
O16.5
23.5​

Answer 1

Answer:

I think 23.5 . don't set me to brainlist just ask questions and I give you answers

Answer 2

If 100g of a metal oxide contains 32 g of oxygen then the equivalent weight of metal will be ...

solution : let chemical formula of metal oxide is M2Ox [ here o.s of oxygen is -2 and o.s of metal is +x ]

molecular mass of M2Ox = 2M + x × 16 [ atomic mass of oxygen is 16 g/mol ]

= 2M + 16x

here we see, (2M + 16x) g of metal oxide contains 16x g of oxygen.

∴ 100g of metal oxide contains 16x/(2M + 16x) × 100g of oxygen

so, 16x/(2M + 16x) × 100 = 32

⇒100x = 4M + 32x

⇒68x = 4M

⇒17x = M

⇒M/x = 17

equivalent weight = atomic weight weight/valency

= M/x = 17

Therefore the equivalent weight of metal is 17.