Question

If 100 grams of N2 is treated with 100 grams of H2,to form

NH3.[N2+ 3H2--->2NH3}At Mass of N is 14.

a) What is the limiting reagent?

b)How many grams of NH3 will be produced ?

please please help me ​

Answer 1

Explanation:

a) N2 is limiting reagent

as 28g of N2 is required for H2 =6g

100g of N2 is required for H2 =(6×100)÷28

= 600÷28

=21.43

b) 28g of N2 produce NH3 =2×(14+3×1)

= 34g

100g of N2 Produces NH3=(34×100)÷28

=3400÷28

=121.43

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