Question

If 100 grams of N2 is treated with 100 grams of H2,to form

NH3.[N2+ 3H2--->2NH3}At Mass of N is 14.

a) What is the limiting reagent?

b)How many grams of NH3 will be produced ?​

Answer 1

Explanation:

a) From standard relation, 28 molar grams of N2 reacts with 6 molar grams of H2 to form 34 molar grams of NH3.

So, taking for 100 molar grams of H2 will react with:

(28*100)/6 = 466.66 grams of N2. Hence N2 is the limiting reagent.

b) Since N2 is limiting, we should take the stoichiometric relation with N2 only.

--> From 28g of N2 ---- 34g of NH3 is produced.

--> From 100g of N2, we get:

(34*100)/28 = 121.43g of NH3 will be produced.

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