Math, asked by khushbujha049, 3 months ago

If ₹100 increases by 8%, it becomes ₹ _____ .
plz ans right​

Answers

Answered by souvik1193
0

Answer:

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Answered by SUNNY90850
5

2125

 \huge \blue{ \overline{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀SOLUTION

 \huge \blue{ \overline{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}

Let the principal be Rs.x.

As it is 100% increased so it becomes Rs. 2x.

Interest = 2x - x = Rs.x.

 \huge \blue{ \overline{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}

 \sf{ \tt{Now,  SI =  \frac{P×R×T}{100} }} \\ \sf{ \tt{x =  \frac{x \times R×8 }{100} }} \\ { \tt{R s= 12.5\%}}

Now CI on Rs.8000 for 2 years is given by

{ \tt{CI = 8000 ×(1 +  \frac{12.5}{100}) {}^{2}  - 8000 }}

{ \tt{Ci = 8000 ×(1 +  \frac{1}{8}) {}^{2}  - 8000 = 8000 \times  }} \\ { \tt{ \frac{9}{8}  \times  \frac{9}{8} - 8000 }}

{ \tt{ =  \frac{81000 - 64000}{8}  =  \frac{17000}{8}  = { \boxed{Rs. \blue{2125}}}}}

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