Question

If 100 ml of 1m koh is diluted to 1 liter the concentration of resulting solution is

Answer 1

Answer:

The concentration of the resulting solution's will be 0.1 M.

Explanation:

Initial concentration of KOH solution = $M_1=1 M$

Initial volume of the KOH solution=$V_1=100 ml=0.1 L$

Final volume of the KOH solution= $V_2=1 L$

Final concentration of KOH solution =$M_2$

$M_1\times V_1=M_2\times V_2$

$M_2=\frac{M_1\times V_1}{V_2}=\frac{1 M\times 0.1 L}{1L}=0.1 M$

The concentration of the resulting solution's will be 0.1 M.