Question

If 100 ml of water requires 5 ml of 0.05 N, EDTA, its hardness is
(a) 200 mg/l
(b) 250 mg/l
(c) 260 mg/
(d) 125 mg/​

Answer 1

Answer:

hey dear

b is correct option .

250 mg / l

hope it's helpful for you.

Answer 2

Answer:

The hardness is 125mg/l.

Explanation:

Milliequivalent of EDTA = 5×0.05

Meq. = 0.25

Therefore, Meq of water = 0.25

We know that milliequivalent weight is given by dividing the weight by equivalent weight. Therefore,

Weight of water = milliequivalent × equivalent weight

Weight of water = $\frac{0.25*100}{1000*2}$

Weight of water = 0.0125

Weight of water = 1.25×10⁻²

Now,

Hardness = $\frac{weight}{volume*density}*10^6$

Hardness = $\frac{1.25*10^{-2}}{100*1}*10^6$

Hardness = 1.25×10²

Hardness = 125mg/l

Therefore, the hardness of water is 125mg/l

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