Chemistry, asked by aimanparmar, 19 days ago

If 1000 mL of water Is added to 500 mL of 5 M NaOH solution, then what will be the amount of NaOH in the final solution?

Answers

Answered by Chemsitrylover
2

Answer:

Metal Carbonates are a type of base that produce a salt, water and carbon dioxide when they react with an acid. Acid + Metal Carbonates → Salt + Water + Carbon Dioxide.f 2 mL of acetone is present in 45 mL of its aqueous solution ,calculate the concentration of this solution , calculate the concentration of this solution .

Explanation:

Hope it will helpful for you thanks..

Answered by Anuiniya
0

Explanation:

Suppose x mole of water be added

no. of mole of NAOH initially =500×0.5×10

−3

=0.25 mole

Mass of NaOH=0.25×40

=10g

Strength =

(500+x)

10

(After addition of water)

500+x

10

=10 mg×10

−3

g

1=0.5+10

−3

x

0.5=10

−3

x

x=500 ml.

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