Question

If 100a+40+3 is divisible by 9,a=

Answer 1

a(mininum) = 2
as it is the value pn which the no. will have its digit's sum = 9s factor.

Answer 2

The divisibility of 9 suggests that if the sum of all digits are divisible by 9, the number is divisible by 9.
here, 100a+43 is the number.
if a=2 then 200+43=243 is divisible by 9.
again, if a= 2+9=11, then 1143 is divisible by 9. continue with +9. u will get ur answers