Question

If 100gm of water at 30 deg C is added to 150gm of water at 60 deg C, find the resulting temperature of the mixture​

Answer 1

20 C is the resulting temperature

Answer 2

Answer:

Specific Heat of water is defined as the amount of heat (added or subtracted) in order to change the temperature of 1 gram of water by 1 degrees Kelvin (or Celsius), under constant pressure.

Let's assume a constant value (c) for the Specific Heat of water, between freezing and boiling temperatures and at atmospheric pressure.

After mixing the water, the total of 300 grams will reach an equilibrium temperature T.

The water originally at 90 degrees temperature will "loose" an amount of heat equal to: Delta Q = c*200 [grams]*(90-T) [degrees].

This same amount of heat will be absorbed by the water originally at 30 degrees to raise its temperature to T. Delta Q = c*100*(T-30).

Now it is easy to solve this equality:

c*200*(90-T) = c*100*(T-30), giving T=70 degrees Celsius.

It will help you

Explanation:

please help me

MARK ME AS BRAINLIEST