if 100kg of calcium crobrate on heating produce 44g of carbon dioxide how much quckline is formed? which law us followed fir solving this problem ????
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Therefore in the said reaction, the mass of CaCO3 should be equal to the mass of total mass of products that is CaO and CO2. 100- 44 = 56 gm. so, 56 gm of quick lime will be produced. this is law of conservation of mass.
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Answer:
This question is based on law of conservation of mass
It states that the mass can neither be created nor destroyed in a chemical reactions.
Therefore the mass of calcium carbonate = mass of Co2 + mass of quick lime
Therefore 100g = 44 + quick lime
= 100 - 44 = quick lime
=56 = quick lime
Therefore the mass of quick lime = 56g
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