if 100kg of calcium crobrate on heating produce 44g of carbon dioxide how much quckline is formed? which law us followed fir solving this problem ????
Answers
Answer:
Answer : 56 gram of quicklime will be formed. The Law of conservation of mass is followed for solving this problem.
Solution : Given,
The mass of calcium carbonate = 100 g
The mass of carbon dioxide = 44 g
The balanced chemical reaction is,
CaCO_3\overset{\Delta }{\rightarrow}CaO+CO_2CaCO
3
→
Δ
CaO+CO
2
Law of conservation of mass : In a chemical reaction, the mass of products must be equal to the mass of reactants.
According to the law of conservation of mass, 100 gram of calcium carbonate will produces 100 gram of products.
The mass of calcium carbonate = 100 gram
The mass of carbon dioxide = 44 gram
Let, The mass of Quicklime = X gram
Mass of calcium carbonate = Mass of carbon dioxide + Mass of Quicklime
100 gram = 44 gram + X gram
X = 100 - 44 = 56 gram
Therefore, 56 gram of quicklime will be formed and the Law of conservation of mass is followed for solving this problem.
Answer:
Therefore in the said reaction, the mass of CaCO3 should be equal to the mass of total mass of products that is CaO and CO2. 100- 44 = 56 gm. so, 56 gm of quick lime will be produced. this is law of conservation of mass