If 100ml 0.05M solution of HCl is diluted 5 times then what will be the PH of resultant solution
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If a solution of pH=5 is diluted 100 times, its pH becomes:
Hard
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Correct option is C)
A strong acid of pH=5 can be considered as 1 litre of pure water, in which 10
−5
moles of a strong acid have been dissolved.
The pH=5 solution diluted 100 times is actually a 10
−7
M solution.
But this time, we are considering the dissociation of acid only.
Now, when water is added, water also dissociates into H
+
and OH
−
.
So, we have to account for the total concentration of H
+
from acid (10
−7
M) and from water(10
−7
M).
In case of infinite dilution of an acid, it is pH=7.
[H
+
]=10
−7
+10
−7
=2×10
−7
pH=−log(2×10
−7
)=7−0.301=6.699
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