Math, asked by manishaunni8007, 18 hours ago

if 100x^2 -b = (10x +1/2) (10x - 1/2),then the value of b is​

Answers

Answered by masterpanshul164
0

Answer:

b= 4

Step-by-step explanation:use identity (a +b)(a-b) = a^2 - b^2

100x^{2} - b = (10x + \frac{1}{2}) ( 10x - \frac{1}{2} )\\                         = 10x^{2}  - \frac{1^{2} }{2^{2} }\\                          = 100x^{2}  - \frac{1}{4} \\100x^{2} - b = 100x^{2} - \frac{1}{4}\\ b = \frac{100x^{2}* 4 }{100x^{2} } \\b = 4\\

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