If 1010 electrons are removed from a neutral body, the charge acquired by the body is
+1.6x10-26C
+1.6x10°C
-1.6x10°C
+10°C
Answers
Answered by
2
(a)n=?
q=-54C
e=1.6*(10)^-19
n=q/e
n=-54/1.6*(10)^-19
n=-3.3*(10)^19
(b)n=?
q=+102C
e=1.6*(10)^-19C
n=q/e
n=102/1.6*(10)^-19
n=70*10^19C
Explanation:
(a)n=?
q=-54C
e=1.6*(10)^-19
n=q/e
n=-54/1.6*(10)^-19
n=-3.3*(10)^19
(b)n=?
q=+102C
e=1.6*(10)^-19C
n=q/e
n=102/1.6*(10)^-19
n=70*10^19C
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Answered by
1
Answer:
+10°C
Explanation:
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