Question

If 101x+99y=0,99x+101y=0,then(x,y)​

Answer 1

The solution (x,y) is (0,0)

Step-by-step explanation:

Given equations are $101x+99y=0\hfill (1)$

and $99x+101y=0\hfill (2)$

Now to solve the given equations to find (x,y) by elimination method

First multiply the equation (1) into 99 on both sides we have

$9999x+9801y=0\hfill (3)$

First multiply the equation (2) into 101 on both sides we have

$9999x+10201y=0\hfill (4)$

Subtracting equations (3) and (4) we get

$9999x+9801y=0$

$9999x+10201y=0$

___(-)____(-)_______________

$-400y=0$

$y=\frac{0}{400}$

Therefore y=0

Substitute y=0 in equation (1) we have

$101x+99y=0$

$101x+99(0)=0$

$101x=0$

$x=\frac{0}{101}$

Therefore x=0

The solution (x,y) is (0,0)

Answer 2

The value of x + y is equal to 5.

Step-by-step explanation:

The complete question:

If 99x + 101y = 400 and 101x + 99y = 600, then x + y is:

Given,

99x + 101y = 400                       ............ (1)

and 101x + 99y = 600                 ............ (2)

To find, the value of x + y = ?

Adding equations (1) and (2), we get

99x + 101y + 101x + 99y = 400 + 600    

⇒ 200x + 200y  = 1000  

⇒ 200(x + y) = 1000  

⇒ x + y = $\dfrac{1000}{200}$

⇒ x + y = 5

∴ The value of x + y = 5

Thus, the value of x + y is equal to 5.

You refer:

https://brainly.in/question/4676915