Question

If 101x313 and 215y173 are divisible by 11 then find x+y​

Answer 1

Answer:

Divisibility rule of 11

(Sum of digits at odd places - sum of digits at even places) should be divisible by 11

923x783

(9+3+7+3)-(2+x+8) = 22 - 10 - x = 12 - x

for 12 - x to be divisible by 11, x = 1

Answer 2

Answer:

It is given that, y 3 y 6 is divisible by 11

So, by divisibility test of 11 difference of alternative sum of digits must be multiple of 11

Therefore we get (1+3+6)−(y+y)=0,11,22

⇒ 10−2y=0,11,22

⇒ 10−2y=0, because for all other options y is negative.

⇒ 2y=10

⇒ y=5

So, number is 15356

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Step-by-step explanation:

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