if 10²⁰¹⁵-2015 is expressed as an integer,what is the sum of its digits
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Answer:
18,128
Step-by-step explanation:
10²⁰¹⁵-²⁰¹⁵
x>1
10⁴-2015=7,895
10⁵-2015=97,985
10⁶-2015=997,985
IN 10^x last 4 digits are always 7,9,8,and 5
sum of digits=(2015-4)9+7+9+8+5
=2011×9+7+8+5
=18099+7+8+5
=18,128
THE ANSWER WAS FOUND BY NEWTON 444
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