Question

If 10g of ag reacts with 1g of sulphur the amount of ag2s formed will be

Answer 1

16Ag + S8 => 8Ag2S

M.W of Ag = 108

M.W of S = 32

16*108 grams of Ag reacts completely with 32*8 grams of Sulphur

=> 1728g Ag reacts completely with 256g of S

=> 6.75g Ag reacts completely with 1g of S (By ratio proportion)

Thus, the remaining 3.25g will not react

=> Mass oh Ag2S formed = 6.75+1 = 7.75g

= 7.75g

Answer 2

Answer:

7.75 g

Explanation:

16Ag + S8 → 8Ag2S

M.W of Ag = 108

M.W of S = 32

 

16*108 grams of Ag reacts completely with 32*8 grams of Sulphur

→1728g Ag reacts completely with 256g of S

→6.75g Ag reacts completely with 1g of S (By ratio proportion)

Therefore, the remaining 3.25g will remain unreacted 

→Mass oh Ag2S formed = 6.75+1 = 7.75g

 

Ans: 7.75g