If 10g of ag reacts with 1g of sulphur the amount of ag2s formed will be
Answers
Answered by
58
16Ag + S8 => 8Ag2S
M.W of Ag = 108
M.W of S = 32
16*108 grams of Ag reacts completely with 32*8 grams of Sulphur
=> 1728g Ag reacts completely with 256g of S
=> 6.75g Ag reacts completely with 1g of S (By ratio proportion)
Thus, the remaining 3.25g will not react
=> Mass oh Ag2S formed = 6.75+1 = 7.75g
= 7.75g
Answered by
1
Answer:
7.75 g
Explanation:
16Ag + S8 → 8Ag2S
M.W of Ag = 108
M.W of S = 32
16*108 grams of Ag reacts completely with 32*8 grams of Sulphur
→1728g Ag reacts completely with 256g of S
→6.75g Ag reacts completely with 1g of S (By ratio proportion)
Therefore, the remaining 3.25g will remain unreacted
→Mass oh Ag2S formed = 6.75+1 = 7.75g
Ans: 7.75g
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