Question

If 10g of CaCO3 is reacted with 10g of HCL what mass of CO2 will be produced​

Answer 1

Explanation:

CaCO3 + 2HCl => CaCl2 + H2O + CO2

In this equation, 1 mole of calicum carbonate reacts with 2 moles of Hydrogen Chloride to produce 1 mole of CO2

No. of moles of CaCO3 (weight is 10g) => 10/100 => 0.1 moles

No. of moles of HCl (weight is 10g) =>

10/36.5 => 0.274 moles approximately

So 0.1 moles of CaCO3 reacts with 0.2 moles of HCl to produce 0.1 moles of CO2 . Thus mass of CO2 produced =>0.1(12+16×2) => 0.1(44) => 4.4 gms. Hope it helps you.

Answer 2

4.4 grams only ......................