Question

IF 10g OF CaCo3 ON HEATING GIVE 4.4 g OF Co2 AND 5.6 g of Cao , SHOW THAT THIESE OBSERVATIONS ARE IN AGREEMENT WITH THE LAW OF CONSERVATION OF MASS .​

Answer 1

Question :

If 10g of CaC$\tt {O}_{3}$ on heating gives 4.4 g of C $\tt {O}_{2}$ and 5.6 g of CaO , Show that these observations are i. agreement with the law of conservation of mass.

Concept :

Law of conservation of mass :

the law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed.

Solution :

Reaction is

$\tt CaC{O}_{3} \longrightarrow C{O}_{2} + CaO$

Reactant : $\tt CaC{O}_{3}$

Products : $\tt C{O}_{2} \:and\:CaO$

Reactant mass = 10 g

Products mass = 4.4 + 5.6 = 10 g

$\therefore$ Reactant mass = products mass

Hence the given observation is in the accordance of law of conservation of mass.

Answer 2

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The observation is in the agreement with the law of conservation of mass

Given:

10g of $CaCo3$ on heating will give 4.4g of co2 and 5.6g of cao

Here $CaCo3$ is considered to be as the reactant and  and CaO are said to be as the products.

To prove the law is law of conservation of mass

Consider,

Mass of reactants in an chemical equation=10g

Mass of products formed due to the chemical reaction=4.4+5.6=10g

Hence, above explanation shows conservation of mass.

From the above expression we can conclude that,

Mass of reactants = mass of products which shows the conservation of mass.

Hence it is proved that the above expression is said to be as the law of conservation of mass.